A 12V battery powers a series circuit with a 4Ω resistor and a 2Ω resistor. Apply Ohm's Law and Kirchhoff's Voltage Law.
Formula Sheet
V = IRSeries: R = ΣRiParallel: 1/R = Σ(1/Ri)P = IV = I²R = V²/RWhat is the total resistance of the circuit (4Ω and 2Ω in series)?
What current flows through the circuit? (V = 12V, R = 6Ω)
What voltage drops across the 4Ω resistor?
Two 6Ω resistors are connected in PARALLEL. What is the equivalent resistance?