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| approach | n=1K | n=1M |
|---|---|---|
| Brute Force | 499,500 | 499,999,500,000 |
| Two Pointers | 1,000 | 1,000,000 |
| Hash Map | 1,000 | 1,000,000 |
1L ← 0; R ← n-12while L < R:3 sum ← a[L] + a[R]4 if sum == target: return (L, R)5 if sum < target: L ← L + 16 else: R ← R - 1
This Two Pointers simulator animates the classic Two Sum problem three ways so you learn the why, not just the trick. Start with the obvious brute-force double loop (O(n²)), then tap over to the two-pointer walk on a sorted array (O(n)) and the one-pass hash map (O(n)) and watch the live operation counter collapse. L and R pointers glide across numbered cells with a running equation readout — for example ‘12 + 2 = 14 = target’ — while a work-to-solve card projects the cost at n = 1,000 and n = 1,000,000, making the difference between quadratic and linear scaling concrete. A synced pseudocode panel highlights the exact line running each step.
two pointers technique · two sum problem · time complexity comparison · brute force vs optimized · hash map lookup · sorted array algorithms · O(n) vs O(n squared)
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