🔋 Electrochemistry Lab

Anode (Oxidation) −Cathode (Reduction) +

Anode [Zn²⁺]: 1.00 MCathode [Cu²⁺]: 1.00 MTemperature: 298 K (25°C)

E° (standard): +1.100 V

E (Nernst): +1.100 V

Q = [Zn²⁺]/[Cu²⁺] = 1.000

ΔG = -212.27 kJ/mol

✓ Spontaneous reaction

Show Electron Flow

E = E° - (RT/nF) × ln(Q)
E = 1.100 - (8.314×298)/(2×96485) × ln(1.000)
E = 1.100 V